Dec 2, 2019
Finding Percent by Mass Ex 1
-- find the percent by mass of O in Fe2O3 -- Fe = 55.846 g/mol -- O = 15.999 g/mol
-- two iron, so 2 ( 55.846 ) = 111.6920 g/mol
-- three oxygen, so 3 ( 15.999 ) = 47.9970 g/mol
-- total mass is 111.6920 + 47.9970 = 159.6890 g/mol
-- percent oxygen = ( total mass of oxygen / total mass ) x 100
-- % O = ( 47.9970 / 159.6890 ) x 100
-- % O = 30.06%
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