So how big does the inner circle need to be in order to put those four points on one straight line?
It turns out to be about 38%. But this is math. We want to know exactly how much and we want to know how to find the answer!
Let's consider the bigger circle a unit circle, so R = 1. Then consider this triangle.
Ten equal sectors define the entire 360°, so they're 36° each. The center-touching angle of this triangle encompasses 2 of those sectors. Therefore, 72°.
Unfortunately, I have to use cosines now. Those who fear trigonometry may want to look away.
Cosine equals adjacent over hypotenuse. We defined the hypotenuse to be 1, because it's a unit circle. So the cosine of 72° is the height of that triangle divided by one. Or just the height of that triangle. h = cos 72°
Now lets look at this slightly different triangle.
That's only 1 out of 10 equal sectors that make up the entire circle. That's a 36° angle. And the cosine of that one is the height of the triangle (the same as the other triangle) divided by the radius of the inner circle — exactly we're trying to find! cos 36° = h / r But we know what h is. cos 36° = cos 72° / r Now we solve for r. r⋅ cos 36° = cos 72° r = cos 72° / cos 36°
That's the exact answer: cos 72° / cos 36°
If you throw it into a calculator, you'll get something like ≈ 0.3819660112510519363...
Like I said, about 38%. Or 38.197%, if you want to be pedantic. Which I hope you do.
And if you don't want your stars straight... that's fine, too. Every star is perfect for someone. ❤️🧡💛💚💙💜









