wednesday 22/03/23
submitted chem ia draft 1!! big step for me honestly and i’m crazy proud of myself for getting here. now all that’s left is cas :D
♫ pro freak - smino ♫

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wednesday 22/03/23
submitted chem ia draft 1!! big step for me honestly and i’m crazy proud of myself for getting here. now all that’s left is cas :D
♫ pro freak - smino ♫
Physiology has never really been my strong suit but I figured if I just compensate with highlighters and colourful pens I can convince myself I know my stuff 👀
Some pages from week 1: Nerves & Synapses
(It took me way way way too long to understand the Nernst equation hence me writing it out in the most simple step by step detail I could figure)
As someone who almost picked an undergrad degree in neuroscience I sure have not enjoyed this topic as much as expected, probably all the math and chem 🤗
Anyone remember how to use the Nernst equation?
The Nernst equation can be used at any time to determine whether a given ion is at equilibrium across a membrane.
"Plant Physiology and Development" int'l 6e - Taiz, L., Zeiger, E., Møller, I.M., Murphy, A.
Movement against a chemical-potential gradient is indicative of active transport (Figure 6.1). (...) Steady state is not necessarily the same as equilibrium (see Figure 6.1); in steady state, the existence of active transport across the membrane prevents many diffusive fluxes from ever reaching equilibrium.
"Plant Physiology and Development" int'l 6e - Taiz, L., Zeiger, E., Møller, I.M., Murphy, A.
\(\textbf{Bioelectrochemistry}\) \[\textit{Nernst Equation Example:}\] \[[K^{+}]\]
After having derived the Nernst equation,
\[V_{eq}=-\frac{RT}{Fz}ln\left[\frac{[C]_{in}}{[C]_{out}}\right]\]
Let us examine how it works. Say for example, in a human neuronal cell, the concentration of \(K^+\) ions outside the cell is \(5mM\), and inside is \(140mM\). The valence, \(z=1\). The equilibrium potential for this concentration gradient of this specific ion (i.e. when the diffusive and electrical potential across the membrane balance), is given by; \[V_{eq}=-26.7ln\frac{140}{5}\approx-89mV\]
When considering that the internal temperatures for biological activity is around \(37^{\circ}C\)
That is to say, at -89mV of potential difference across the cell membrane(the inside being more electronegative), there will be no net movement across the cell membrane for this ion.
\(\textbf{Neurophysiology}\) \[\textit{The Hodgkin-Huxley Model}\] \[\textit{Part 1 - Nernst Equation}\] \[V_{eq}=-\frac{RT}{zF}ln\frac{[C_{in}]}{[C_{out}]}\]
The Hodgkin-Huxley model for neuronal activity is one of the most well studied. It is also the inspiration for the perceptron and neural network models found in machine learning algorithms of today. More than that however, it was one of our first insights into a physiological mechanism, which to this day, is still in the process of being unraveled.
In explaining the fundamentals of this model, we will walk along a winding road full of neat and often clever mathematical descriptions which will inevitably build upon each other until we arrive at our destination. The first stop, per the title, is the Nernst Equation.
The \(\textit{membrane potential}\) of a cell, is the potential difference between the inside and outside of a cell across its membrane.
\[V_m=V_{in}-V_{out}\]
The \(\textit{resting potential}\) is the potential across the cellular membrane when the cell is at rest, with the inside being more electronegative. The typical value for a neuron is \(-70mV\).
The \(\textit{equiibrium potential}\) across a membrane for a particular ion is the potential at which the electrical and diffusive movement are equal and opposite, such that there is no net movement across the membrane for that ion. The following relation must therefore be satisfied
\[J_{diff} + J_{drift} = 0\]
From Fick’s law [1]:
\[J_{diff} \propto \frac{\partial [C]}{\partial x}\]
From Ohm’s Law [2]:
\[J_{drift} \propto z[C]\frac{\partial V}{\partial x}\]
Where \([C]\) is the concentration, and \(V\) is the potential of the given ion at the point \(x\) across the membrane.
It is found by the Einstein relation [3] that, adjusting the coefficients of these terms and summating them, we arrive at the Nernst-Planck equation [4]; an expression for the \(\textit{current flux}\), \(I\)
\[I=-uzRT\frac{\partial [C]}{\partial x}-uz^2F[C]\frac{\partial V}{\partial x}\]
At \(I=0\), we can evaluate the equilibrium potential for ions passing through an open channel by solving the differential equation
\[-uzRT\frac{\partial [C]}{\partial x}-uz^2F[C]\frac{\partial V}{\partial x} =0\]
\[\frac{\partial V}{\partial x} = -\frac{RT}{Fz}\frac{1}{[C]}\frac{\partial [C]}{\partial x}\]
Summating over the domain (from \(x=0\) to \(x=l\), where \(l\) is the thickness of the membrane), which is from the inside to the outside of the cell, we arrive at
\[\int_{out}^{in}VdV=-\frac{RT}{Fz}\int_{out}^{in}\frac{1}{[C]}d[C]\]
\[V_{eq}=-\frac{RT}{Fz}ln\frac{[C_{in}]}{[C_{out}]}\]
This equation provides the equilibrium potential given a concentration gradient of ions across an open channel.
This equation assumes that the ions do not interact, and that the medium of the flux is aqueous. Typically, cell membranes behave in a more complex way, however, deriving this equation is a good start for a simplified model.
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