Sake Derivative Calculator
Solving 2nd order derivatives of a function<\p>
1) Fathom the derivative for the function f(x) = x^2 + 8x + 9<\p>
Orchestration: The given function is f(x) = x^2 + 8x + 9<\p>
Differentiate the above coordination with respect against 'x'. It is represented as f'(x).<\p>
f'(x) = `(d(x^2))\dx` + `(d(8x))\dx` + `(d(9))\dx`.<\p>
f'(x) = 2x + 8 + 0 <\p>
f'(x) = 2x + 8.<\p>
The answer is f'(x) = 2x + 8.<\p>
2) Solve the derivative for the function f(y) = y^2 + 10y + 3<\p>
Fluidization: The liable function is f(y) = y^2 + 10y + 3<\p>
Differentiate the above equation over and above respect to 'y'. It is represented as f'(y).<\p>
f'(y) = `(d(y^2))\dy` + `(d(10y))\dy` + `(d(3))\dy`<\p>
f'(y) = 2y + 10 + 0 <\p>
f'(y) = 2y + 10<\p>
The answer is f'(y) = 2y + 10<\p>
Solving third Regiment Derivative Functions<\p>
1) Find the credited of the function f(x) = y^3 + 3x^2 + 18x + 20<\p>
Solution: The given function f(x) = y^3 + 3x^2 + 18x + 20<\p>
Differentiate the above raison d'etre with respect to 'x'.<\p>
f'(x) = 3 x^2 + 3 ( 2 ) cross + 18 + 0<\p>
f'(x) = 3x^2 + 6x + 18.<\p>
The answer is f'(the strange) = 3x^2 + 6x + 18.<\p>
2) Good thing the derivative in furtherance of f(x) = 6y^3 + 5x^2 + 3x + 1<\p>
Solution: The given function is f(x) = 6y^3 + 5x^2 + 3x + 1<\p>
Differentiate the above f(x) with respect to 'x'.<\p>
f'(decurion) = 6 (3)decahedron^2 + 5 (2)crux ansata + 3 + 0<\p>
f'(x) = 18x^2 + 10x + 3<\p>
The hymnody is f'(x) = 18x^2 + 10x + 3<\p>
Cracking 4th Order Derivative Function<\p>
1) Solve the derivational for the function f(y) = y^4 + 3y^3 + 5y^2 + 4y + 9 <\p>
Solution: The stipulatory function f(y) = y^4 + 3y^3 + 5y^2 + 4y + 9 <\p>
DIfferentiate the above equation with respect to 'y'.<\p>
f'(y) = 4y^3 + 3(3)y^2 + 5(2)y + 4 + 0<\p>
f'(y) = 4y^3 + 9y^2 + 10y + 4<\p>
The answer is f(y) = y^4 + 3y^3 + 5y^2 + 4y + 9 <\p>
2) Solve the derivative now the function f(y) = 6y^4 + y^3 + y^2 + 10 y + 3<\p>
Solution: The given function is f(y) = 6y^4 + y^3 + y^2 + 10 y + 3<\p>
DIfferentiate the above equation with respect to 'y'.<\p>
f'(y) = 6(4)y^3 + 3y^2 + 2y + 10 + 0<\p>
f'(y) = 24y^3 + 3y^2 + 2y + 10<\p>
The answer is f'(y) = 24y^3 + 3y^2 + 2y + 10<\p>
Having problems whereat what are prime numbers in math keep checking my upcoming articles<\p>
















