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Proof: If a and b are relatively prime so that gcd(a, b) = 1. Then the theorem( “ Given integers a and b, not both of which are zero, there exist integers x and y say that gcd(a, b) = ax + by”) guarantees the existence of integers x and y satisfying 1 = ax + by. As for the converse, suppose that 1 = ax + by for some choice of x and y, and that d = gcd(a, b). Since d\a and d\b, then d\(ax + by), or d\1. In as much as d is a positive integer, this last divisiblity condition forces d to equal 1and the desired conclusion follows.
Relatively Prime: Let a and b integers not both zero are said to be relatively prime whenever gcd(a, b) = 1.
