NOTE:This decimal converted binary value will be use through out this post.
128 64 32 16 8 4 2 1
Before we go to subnetting process. Let us review the IP address and network mask. Let us site an example.
Given 192.168.200.0 /24 ip address block. Let's try to interpret how network device will read this.
Take a look on Network Mask (binary value). Just remember that all
Also, remember that each address should have network address, usable host range and broadcast address. For the network device (such as router) to properly locate the specific host or target.
Let us get started.
Looking at the example above. How do we identify the network,host and broadcast address?
To compute for Network ID (or network address) - we use Logical AND (or we should I say multiply) IP address (binary value) to Network Mask (binary value)
To compute for Broadcast address - Bring down the network address + convert binary host portion to 1
To define the Usable address - the number start after NETWORK ID and it ends before BROADCAST ID. The number of usable address can be computed also by 2n - 2; where "n" = number of host bits.
I hope above information encourage you to know subnetting :). Now let us tackle subnetting.
Subnetting
is the process to create small group of network to maximize the use of IP address block buy borrowing a binary bit/s (called subnet ID) from the host portion (in binary value).
“On this post I will try to explain the proper procedure and the shortcut that I know. It is on your decision which procedure is more convenient for you.”
Subnetting - Proper Method
Procedure:
1. Determine the classful network mask if the prefix is not define.
2. Determine how many subnet bits needed for the required number of networks. Use this formula 2 raise to subnetid = number of required networks. And look for the new network mask (called subnet mask)
3. Determine the Delta (sometimes called Increment); where Delta = to the decimal value of the right most binary 1.
4. Plot the network, usable and broadcast address and its subnet mask
Example1:
Given: 192.168.35.0
How many networks do I need for above diagram? The Answer is 4. (Remember in CCNA each router interface is 1 broadcast domain)
What are the IP address I can assign to each router interface and to hosts?
Let us use the procedure above.
1. Determine the classful network mask if the prefix is not define.
Answer is 255.255.255.0 (since the given address is part of Class C)
2.Determine how many subnet bits needed for the required number of networks. Use this formula 2 raise to subnetid = number of required networks. And look for the new network mask (called subnet mask)
Needed networks = 4
We are after really about subnet bits.
Therefore;
3. Determine the Delta (sometimes called Increment); where Delta = to the decimal value of the right most binary 1.
The right most binary 1 is located on the Octet 4. Using 128 64 32 16 8 4 2 1 value,
Delta = 64
Subnet mask = 255.255.255.192 (/26)
4. Plot the network, usable and broadcast address using value of Delta and its subnet mask
4.a. plot the Network address; Delta = 64
4.b. plot the Broadcast address. The last address before the next Network address is a broadcast address.
4.c. plot the Usable address. These are the adress range between Network Address and Broadcast Address.
Please NOTE that we are not assigning Network and broadcast address to any devices.
Let us assign the IP address to each network device interfaces.
Subnetting - Shortcut method
( Aha! so may shortcut pala! )
Actually you just need to memorize the procedure, formula and by practice.
Procedure (Looking for numberof network address)
1. Using our hand to compute the subnet bits. Using this Formula 2 4 8 16 32 64 128 256 512 1024 and so on...
2. Look Delta and subnet mask
3. Plot the network address
Example:
Given 192.168.20.0 : Required 16 network.
1. Using our hand to compute the subnet bits. Using this Formula 2 4 8 16 32 64 128 256 512 1024 and so on...
The formula I'm using is counting this on using my starting from 2 4 8 16 32 64 128 256 512 1024 and so on...
since I need 16 network, using the formula above how many finger I used.
Above information - means that we need 4 subnet bits to create 16 network.
2. Look Delta and subnet mask
Delta = 16
Subnet Mask = 255.255.255.240 (/28)
Remember that Delta is the right most binary bit 1 (in decimal form) of a new netmask which is 16
For Subnet Mask - 128+64+32+16 = 240
3. Plot the network address
The increment of each subnet is 16 as we seen above. I only look for the NETID (network address) because from there we can identify the usable address and broadcast address.
Network Address for network1 = 192.168.20.0 /28
Usable address for network1 = 192.168.20.(1 - 14) /28
Broadcast address of network1 = 192.168.20.15 /28
1. Counting again by hand and using this formula again 2 4 8 16 32 64 128 256 512 1024..so on (minus 2 )
2. Plot the host portion
3. Look Delta and subnet mask
4. Plot the network address
Example: 192.168.0.0 ; required 16 hosts per subnet.
1. Counting again by hand and using this formula again 2 4 8 16 32 64 128 256 512 1024..so on (minus 2 )
Using this formula again 2 4 8 16 32 64 128 256 512 1024..so on (minus 2 )
Here, we should focus on the host portion. Means how many host bits (0) do we need to cater 16 hosts per subnet?
This example is tricky! Is it correct that we only need 4 host bits? Answer is NO. Remember, IP address block should have network and broadcast address. That is the reason why we need to subtract 2.
because 16 -2 = 14 host only. We need to add another host bit.
And the correct answer should be below.
Host bits = 5
which is 32 -2 = 30 hosts per subnet.
2. Plot the host portion
OK! Now I know the host bits. How will i know the subnet mask , and NET ID for each subnet.
Check the given again. 192.168.0.0 is part of class C. Means that the default nework mask is /24 (or 255.255.255.0)
Meaning we cannot modify the first 3 octet. Because subnetting is borrowing subnet bits from the host portion. In Class C network. the host portion is Octet4.
Procedure here is to plot the "0s" from right to left. The rest make "1s".
3. Look Delta and subnet mask
From above table, we can now determine the other subnetting requirements.
4. Plot the network address
Another example: (This time try to use your mind to get the answer)
Given: 10.16.0.0 /8; Required 100 users per subnet.
VLSM (Variable Length Subnet Mask)
This subnetting technique is commonly used by networks today to maximize the use of IP address block by creating different subnet size. If you will notice, subnetting can divide classful network. But they still found out some waste of usable address.
For example we have a IP block with a prefix of /25 - meaning 126 address are the usable address and for point-to-pint connection only 2 address are needed and the rest will be unused.
And most of the time engineers are focus on usable address for each block when doing this.
Giving an example:
NOTE:
For VLSM - always create the subnet the largest first to smallest network requirement.
The rest are the same with subnetting procedure. Let us start by defining the required network from largetst to smallest.
So we finish the VLSM table. Let us know assign these addresses to our network design above.
In practical world, VLSM is commonly use but you need to give allowance on your computation for your company future expansion.
That is the reason, why large company uses class A (10.X.X.X) for their internal network communication.
Try to follow my example until you become familiar with the computation.
Supernetting / CIDR / Route summarization
I would say Supernetting is most commonly use by engineers for route summarization. It is a summarization of a multiple subnets under a common network prefix - also known as CIDR (Classles Inter Domain Routing).
Procedure:
1. Plot the network address in binary value.
2. On all of the network address, look for the significant bit which is common to all network address bits. Count the number of common bits
3. Find the summarize network address prefix and subnetmask
Example:
On the diagram below, R1 wants to see a summarize network for each company. In order to provide the requirement. R2 and R3 needs to advertise their summarize network towards R1.
1. Plot the network address in binary value.
2. On all of the network address, look for the significant bits which is common to all network address bits. Count the number of common bits
3. Find the summarize network address prefix and subnet mask.
Using the value we got above, we can now use it for R2 and R3 to advertise their summarize attached networks towards R1
In R1 routing table, it should be like this
192.168.0.0 / 19 via R2 directly connected address
172.16.0.0 /17 via R3 directly connected address
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There are tons of explanation in the internet describing what is an IP address , On this section, I will try to simplify it for you to understand it more clearly.
what is IP address ?
- it is a 32-binary bits address that can be assign uniquely to a host
- 32 binary bit means 4 octets divided by a dot "." (machine language)
- in human readable - ip address is in a form of 4 decimal value divided by a dot "."
example:
This binary arithmetic should be easy to those who finish their CCNA course. You will see tons of explanation on the internet to compute this. On this blog I will show you how I compute this. Trying to make it more easy and faster.
I memorize below value (a decimal converted value from binary) and this value are computed the same to all octets.
128 64 32 16 8 4 2 1
Setting an example. Converting Octet 2 on IP address sample above. Only look for "1s" on the binary bits and add the decimal value
Computation for Octet 2
Lets take Octet 4 for another example
Computation for Octet 4
NOTE: We will be using this decimal convertion value to the rest of IP addressing. So please take note of these value.
128 64 32 16 8 4 2 1
Classful IPv4 address
Classful adress are IP address ranges that are FIX and terms of network mask and divided into two (2) parts - network bits and host bits. For some, they called it as network portion and host portion.
- It is divided into five (5) classes -- A, B, C, D, E
class A , B, C - commonly use for host or device addressing.
class D - for multicasting
class E - for experimental use
So how do we determine the Classful network. First thing, we need to know the network mask of each type. Remember that IP address is consist of 4 octet binary bits like below.
Octet1 . Octet2 . Octet3 . Octet4
The rule here is to make all "1" on each octet. And sum all "1" using decimal convertion as explain above. Please take a look also that I am indicating the Network portion and Host portion.
class D and E - network mask is not applicable.
In a classful network, these network mask value in a classful address are FIX.
So how do we know if the ip address is part of which type? how do we compute the IP address range of each classess. The answer is revealed on this "1st Octet rule"
1st Octet rule - is the process to modify the left most (high-order bits) of octet 1. Where X (on this example) is variable and each class has its constant value.
Computing the number of Network and Host of each class
Below is the table how to compute the number of usable network and host address on each class.
Take a look on class A (total # of Network) why the computation become 2raise to 7 - 2 (with -2). The reason behind this is that we are removing network 0.0.0.0 and 127.0.0.0.
0 - is use as default. Some says it is used for broadcast.
127 - is reserved for loopback address
Now have a look on Total # of host. Why do we subtract 2 on each class. The reason behind that; each IP address block has NetworkID - Host ID. And we cannot use these as usable address.
Why we cannot use it. Each IP address block consist of
Nework ID - used by router to where the packet should it forward
Usable Host ID - an address that can be use by hosts or devices
Broadcast ID - use for broadcast. Normally to create MAC adn ARP table to reach the target host.
To give you a clear picture. Let us say we have 192.168.100.0 /24
we now know that this is a Class C given that the first octet is 192 and the network mask is 255.255.255.0 (/24).
192.168.100.0 - is network ID or address use by router to reach below usable address.
192.168.100. 1 -- 254 - is the usable address
192.168.100.255 - is the broadcast ID or address to locate the specific host via MAC or ARP table.
Summarizing everything above we should come up with below table. You dont need to memorize this as long you know how to compute this values. Trying read again above information and compute it for yourself. ("I understand you - medyo boring ito :)"
Private IP Address
Above are the ranges can be use by any company for their internal network communication. And if they want to reach internet they need to use NAT or web proxy application.
These are define under RFC 1918 to conserve IPv4 addresses.
They also introduce IPv6 address to provide sufficient unique address across the globe. (I will try to read about IPv6 addressing and will post on this blog about what I learned.)
Classful vs Classless Network
We already discuss about classful networks above. These are the networks that uses FIX network mask.
To review:
Classless
So what is classless networks? These are the networks derive from classful network to create small group of networks by borrowing binary bits from the host portion. This bit is called Subnet bit or subnet ID. The process of doing this is called Subnetting.
Too give you an idea please have a look on below table.
Before moving to Subnetting, VLSM, and supernetting (IP Addressing - part 2). We need to understand this information first.
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