Fly Me To The Moon (for about $2500)
I love doing orbital ring math when I'm stressed. It's a shockingly good way to distract myself. So... Let's talk about a journey from the Earth to the Moon.
The three Apollo astronauts of each mission experienced peaks of 5 Gs on launch and 6-7 Gs on reentry (each for about 30 seconds). They then spent ~36 hours in transit each way, in the cramped command module.
Passengers traveling from the Earth to the Moon -- in a situation where we have orbital rings at both -- would have a very, very different experience. They'd take trains from the ground up to the rings, then board their spacecraft to the moon. Space or cargo capacity would be non-issues, so these could be very well-appointed shuttles, serving food and drinks and having comfortable seats not unlike a nice train or first-class aircraft cabin.
Once aboard, they'd begin accelerating around the ring, purely using electrical drive systems -- no rockets. They'd experience up to 1.6 Gs over the course of 6 minutes before being released from the ring and flying towards the moon. For the next 10.5 hours, they'd experience weightlessness as they hurtled towards the moon.
Once arriving at the moon's orbital ring, their craft would be captured and begin decelerating, experiencing a peak force of 3g at the beginning of a 3 minute deceleration. At which point they could take a nice train down to the surface!
Before profit, paying the flight attendants, and accounting for spacecraft maintenance, the cost per person on a 100 passenger flight would come out to around $1500 to travel from the Earth to the Moon. Call it $2500 with overhead. The cost to return to Earth is similar, leading to a round-trip ticket cost of $5000 per passenger for a lunar vacation.
