JEE File Upload - Handling Multipart requests in Servlets 3.0
Prior to Servlets 3.0 developers have to use 3rd party libraries to process complex multipart request that is sent when file is uploaded by user. Starting from Servlets 3.0 JEE provides a better way to handle file uploads (multipart requests) without using any 3rd party library.
Making your Servlet ready to handle Multipart requests
All you have to do is to add @MultipartConfig annotation on your servlet class and it is ready to handle Multipart requests.
public class FileUploadServlet extends HttpServlet {
<form method="POST" enctype="multipart/form-data">
<input type="file" name="ufile" />
<input type="submit" value="Submit" />
</form>
Handling the POST in processRequest method of Servlet
protected void processRequest(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
Getting the uploaded file Part
To extract the uploaded file we will use getPart method of HttpServletRequest. getPart method returns a part from multipart request specified by name passed as parameter to it.
Part filePart = request.getPart("ufile");
Getting file name of uploaded file
Even though we have now support in servlets to handle Multipart request we have to do some extra processing to get the file name and other things from the Part. We will make a helper function that will return the filename passed from client's browser to our server in the <input type=file> object.
//Content-Disposition for uploaded file has following format
//form-data; name="ufile"; filename="name.txt"
private String getFileName(final Part part) {
final String partHeader = part.getHeader("content-disposition");
for (String content : part.getHeader("content-disposition").split(";")) {
if (content.trim().startsWith("filename")) {
return content.substring(
content.indexOf('=') + 1).trim().replace("\"", "");
}
}
return null;
}
We will call the helper function like this
final String fileName = getFileName(filePart);
//we will construct the path to save the file.
//Right now I am making dummy path for simplicity
String filePath="D:\\"+fileName;
Reading from uploaded file Stream and writing to local file
As standard in Java we will need OutputStream of file where we will store our uploaded file and InputStream for uploaded file. Part class has a method getInputStream() that returns the InputStream to read the bytes/data of that Part.
InputStream filecontent = filePart.getInputStream();
OutputStream fileOut = new FileOutputStream(new File(filePath));
Start reading from InputStream and write to OutputStream
int read = 0;
final byte[] bytes = new byte[1024];
while ((read = filecontent.read(bytes,0,1024)) != -1) {
out.write(bytes, 0, read);
}
if (out != null) {
out.close();
}
if (filecontent != null) {
filecontent.close();
}
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