Discover Top Posts Tagged with #----------------------------------

Coining + Text post blog

Run by an anonymous side-system, he/it pronouns (it/its preferred) and neu/masc terms

➤ Post ideas

➤ Request/Archival info

➤ Anon list (none so far)

➤ Archive

#----------- TAG LIST -----------#!! not flags #!! flags #!! requests #----------------------------------#intro post done by 🫀💛

Background

Using devices such as Jawbone Up, Nike FuelBand, and Fitbit it is now possible to collect a large amount of data about personal activity relatively inexpensively. These type of devices are part of the quantified self movement – a group of enthusiasts who take measurements about themselves regularly to improve their health, to find patterns in their behavior, or because they are tech geeks. One thing that people regularly do is quantify how much of a particular activity they do, but they rarely quantify how well they do it. In this project, your goal will be to use data from accelerometers on the belt, forearm, arm, and dumbell of 6 participants. They were asked to perform barbell lifts correctly and incorrectly in 5 different ways. More information is available from the website here: http://groupware.les.inf.puc-rio.br/har (see the section on the Weight Lifting Exercise Dataset).

Data

The training data for this project are available here:

https://d396qusza40orc.cloudfront.net/predmachlearn/pml-training.csv

The test data are available here:

https://d396qusza40orc.cloudfront.net/predmachlearn/pml-testing.csv

The data for this project come from this source: http://groupware.les.inf.puc-rio.br/har. If you use the document you create for this class for any purpose please cite them as they have been very generous in allowing their data to be used for this kind of assignment.

What you should submit

The goal of your project is to predict the manner in which they did the exercise. This is the "classe" variable in the training set. You may use any of the other variables to predict with. You should create a report describing how you built your model, how you used cross validation, what you think the expected out of sample error is, and why you made the choices you did. You will also use your prediction model to predict 20 different test cases.

---------------------------------------------------------------

# Load the packages useful for the analysis

library(caret)

library(randomForest)

# Load data provided on Coursera

# Any blank value is replaced by "NA"

training <- read.csv("pml-training.csv", na.strings = c("NA", ""))

testing <- read.csv("pml-testing.csv", na.strings = c("NA", ""))

# Take a look to number of rows and variables

dim(training)

dim(testing)

# training -> 19622 rows, 160 variables

# testing -> 20 rows, 160 variables

# See the structure

str(training)

str(testing)

# Remove all the columns that show any missing values

training_1 <- training[, colSums(is.na(training)) == 0]

testing_1 <- testing[, colSums(is.na(testing)) == 0]

# Remove the first seven colums as they have no such predictive power to "classe"

training_2 <- training_1[, -c(1:7)]

testing_2 <- testing_1[, -c(1:7)]

# So, take again a look to number of rows and variables

dim(training_2)

dim(testing_2)

# training -> 19622 rows, 53 variables (variables have been reduced, as consequence)

# testing -> 20 rows, 53 variables (variables have been reduced, as consequence)

# Set a seed in order then to have a new training set (split is 70%) for prediction and

# a validation set (split is 30%).

set.seed(1234)

PartTrain <- createDataPartition(training_2$classe, p = 0.7, list = FALSE)

train <- training_2[PartTrain, ]

valid <- training_2[-PartTrain, ]

# Train a model using random forest with a k-fold cross validation

mod_rf <- train(classe ~., method="rf", data=train, trControl=trainControl(method='cv'),

number=5, allowParallel=TRUE, importance=TRUE )

print(mod_rf)

# Print and show result

# Random Forest

# 13737 samples

# 52 predictor

# 5 classes: 'A', 'B', 'C', 'D', 'E'

# No pre-processing

# Resampling: Cross-Validated (10 fold)

# Summary of sample sizes: 12365, 12365, 12362, 12361, 12363, 12364, ...

# Resampling results across tuning parameters:

# mtry Accuracy Kappa

# 2 0.9922856 0.9902402

# 27 0.9931575 0.9913439

# 52 0.9903183 0.9877527

# Accuracy was used to select the optimal model using the largest value.

# The final value used for the model was mtry = 27.

# Plot

varImpPlot(mod_rf$finalModel, sort = TRUE, type = 1, pch = 25, col = "red", cex = 0.7,

main = "Principal components: IMPORTANCE", sub = "ORDERED")

# Graph shows the principal components in order of importance

pred_rf <- predict(mod_rf, valid)

confusion <- confusionMatrix(valid$classe, pred_rf)

print(confusion$table)

# Print and show the table result

# Reference

# Prediction A B C D E

# A 1674 0 0 0 0

# B 11 1127 1 0 0

# C 0 3 1019 4 0

# D 0 2 6 954 2

# E 0 1 2 3 1076

# A few cases are not properly predicted

# Estimate accuracy

accuracy <- postResample(valid$classe, pred_rf)

Fit_Accuracy <- accuracy[[1]]

print(Fit_Accuracy)

# Print and show result of accuracy rate

# [1] 0.9940527

# Calculate out-of-sample error rate

1-0.9940527

# [1] 0.0059473

# There is high correlation between the variables

prediction <- predict(mod_rf, testing_2)

print(prediction)

# [1] B A B A A E D B A A B C B A E E A B B B

# Levels: A B C D E

#----------------------------------

Background

Data

The training data for this project are available here:

https://d396qusza40orc.cloudfront.net/predmachlearn/pml-training.csv

The test data are available here:

https://d396qusza40orc.cloudfront.net/predmachlearn/pml-testing.csv

What you should submit

---------------------------------------------------------------

# Load the packages useful for the analysis

library(caret)

library(randomForest)

# Load data provided on Coursera

# Any blank value is replaced by "NA"

training <- read.csv("pml-training.csv", na.strings = c("NA", ""))

testing <- read.csv("pml-testing.csv", na.strings = c("NA", ""))

# Take a look to number of rows and variables

dim(training)

dim(testing)

# training -> 19622 rows, 160 variables

# testing -> 20 rows, 160 variables

# See the structure

str(training)

str(testing)

# Remove all the columns that show any missing values

training_1 <- training[, colSums(is.na(training)) == 0]

testing_1 <- testing[, colSums(is.na(testing)) == 0]

# Remove the first seven colums as they have no such predictive power to "classe"

training_2 <- training_1[, -c(1:7)]

testing_2 <- testing_1[, -c(1:7)]

# So, take again a look to number of rows and variables

dim(training_2)

dim(testing_2)

# training -> 19622 rows, 53 variables (variables have been reduced, as consequence)

# testing -> 20 rows, 53 variables (variables have been reduced, as consequence)

# Set a seed in order then to have a new training set (split is 70%) for prediction and

# a validation set (split is 30%).

set.seed(1234)

PartTrain <- createDataPartition(training_2$classe, p = 0.7, list = FALSE)

train <- training_2[PartTrain, ]

valid <- training_2[-PartTrain, ]

# Train a model using random forest with a k-fold cross validation

mod_rf <- train(classe ~., method="rf", data=train, trControl=trainControl(method='cv'),

number=5, allowParallel=TRUE, importance=TRUE )

print(mod_rf)

# Print and show result

# Random Forest

# 13737 samples

# 52 predictor

# 5 classes: 'A', 'B', 'C', 'D', 'E'

# No pre-processing

# Resampling: Cross-Validated (10 fold)

# Summary of sample sizes: 12365, 12365, 12362, 12361, 12363, 12364, ...

# Resampling results across tuning parameters:

# mtry Accuracy Kappa

# 2 0.9922856 0.9902402

# 27 0.9931575 0.9913439

# 52 0.9903183 0.9877527

# Accuracy was used to select the optimal model using the largest value.

# The final value used for the model was mtry = 27.

# Plot

varImpPlot(mod_rf$finalModel, sort = TRUE, type = 1, pch = 25, col = "red", cex = 0.7,

main = "Principal components: IMPORTANCE", sub = "ORDERED")

# Graph shows the principal components in order of importance

pred_rf <- predict(mod_rf, valid)

confusion <- confusionMatrix(valid$classe, pred_rf)

print(confusion$table)

# Print and show the table result

# Reference

# Prediction A B C D E

# A 1674 0 0 0 0

# B 11 1127 1 0 0

# C 0 3 1019 4 0

# D 0 2 6 954 2

# E 0 1 2 3 1076

# A few cases are not properly predicted

# Estimate accuracy

accuracy <- postResample(valid$classe, pred_rf)

Fit_Accuracy <- accuracy[[1]]

print(Fit_Accuracy)

# Print and show result of accuracy rate

# [1] 0.9940527

# Calculate out-of-sample error rate

1-0.9940527

# [1] 0.0059473

# There is high correlation between the variables

prediction <- predict(mod_rf, testing_2)

print(prediction)

# [1] B A B A A E D B A A B C B A E E A B B B

# Levels: A B C D E

#----------------------------------

#----------------------------------

Trending Tags

Recently Viewed Tags

#----------------------------------