Whenever we have 366 days in a year instead of 365 days, that year is called a leap year. Leap year comes every fourth year. This adjusts the calendar year with the solar year.In this tutorial, we will learn to write a C program to check whether a given year is a leap year or not.Problem Statement:Write a C program to check whether a year is a leap year or not.Here our program will take integer input from the user.It should print if the result on the screen. We will be using if-else statement to make this program.Program #include int main(){ int year; printf("Enter a year: "); scanf("%d", &year); if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) printf("%d is a leap year", year); else printf("%d is not a leap year", year); return 0;} Example:Input 1: 2000 Output:2000 is a leap yearInput 2: 2001 Output:2001 is not a leap yearProgram Explanation:- We have included stdio.h to enable the program to do input and output operations.- The main() function is the entry point of any C program.- Here, we have declared the variable 'year' of integer type to store user input.- printf() function is used to show the output/message on the display.- scanf() function is used to read the input year given by the user.- if-else statement is used to apply check whether the given year is divisible by 4 and 100.- The return statement returns 0 to the operating system and denotes the end of a program.Conclusion:In this blog, we have written a C program to check whether a year is a leap year or not using the if-else statement.The above program takes a integer as input from the user.And After taking input, with the help of if else statement it checks whether the number is divisible by 4 and 100 or divisble by 400.I hope this blog was helpful to you in understanding the C program.