time to share one of my favorite poems
Interview Vampire Daily

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Cosmic Funnies
Sade Olutola
ojovivo
I'd rather be in outer space 🛸

Discoholic 🪩

ellievsbear
Cosimo Galluzzi
Fai_Ryy
YOU ARE THE REASON
Claire Keane
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TMBGareOK. The Official They Might Be Giants tumblr
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"I'm Dorothy Gale from Kansas"

bliss lane
sheepfilms
🩵 avery cochrane 🩵

if i look back, i am lost
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@asolacion
time to share one of my favorite poems
Burrowing Owl (Athene cunicularia), family Strigidae, order Strigiformes, Southern CA, USA
photo by Birds of Rey Wildlife Photography
It was dreamlike. Nightmarish? Not always. Sometimes it was beautiful.
ANNIHILATION (2018) dir. Alex Garland
its not funny but i do think about it a lot
This made me think about this panel from Calvin and Hobbes:
But unlike the adult in this strip, Calvin’s dad actually APOLOGIZED for yelling at him when he saw how guilty his kid was:
me if i was a furry
Convoy near Kita, Mali
French vintage postcard
DIRT documents: [# 5]
Drift stitching is a repair method where zip ties, wires, or clips are used to hold cracked parts together after an accident.
The technique became popular in drifting and motorsports because damaged bumpers could be repaired quickly without replacing the entire panel. Small holes are drilled along the crack so the material can be stitched back together and reinforced.
Over time, the repair style spread beyond racing and became common in DIY car culture. People have also used this method on motorcycles and anything in need of a temporary fix that doesn’t immediately hurt the wallet.
Some people use drift stitching purely for function, while others leave the stitching visible as part of the aesthetic.
𝔞 𝔥𝔬𝔪𝔢 𝔱𝔬 𝔠𝔞𝔩𝔩 𝔶𝔬𝔲𝔯𝔰
I recently learned about the penis snake, a caecilian that is the world's largest lungless tetrapod. Do you have any examples of lovely caecilians to share?
Yes this is one of my fav groups of animals!
Herps and Birds (and More) — Eiselt's Caecilian aka "Penis Snake" Caecilian...
Ringed Caecilian (Siphonops annulatus), family Siphonopidae, widely distributed in South America, east of the Andes
Caecilians are amphibians, like frogs and salamanders. (They are not worms, nor are the snakes).
Most species are fossorial (burrowing), but many are also aquatic or semi-aquatic.
photograph by Carlos Jared
Kaup’s Caecilian (Potomotyphlus kaupii), family Typhlonectidae, found in northern South America
This species is aquatic.
photograph by Dante Fenolio
Beddome’s Caecilian (Ichthyophis beddomei), family Ichthyophiidae, western India
photograph by Girish Gowda
Magdalena Valley Caecilian (Caecilia subnigricans), family Caeciliiidae, San Jacinto, Bolivar, Colombia
photograph by José Gabriel Julio Guzmán
São Tomé Caecilian (Schistometopum thomense), family Dermophiidae, endemic to São Tomé and Ilhéu das Rolas (Africa)
photographs by m_burger
m1=28.9 m2=89.7 m3=21.2 (solar masses) v1x=2.801 v1y=5.894 v2x=-5.067 v2y=5.171 v3x=1.238 v3y=-3.291 (km/s) x1=25.0 y1=4.0 x2=-22.0 y2=30.0 x3=14.0 y3=-34.0 (AU from center) Music: Moonlight Sonata (1st Mvmt) – Beethoven
Me walking into my professor's office for a meeting:
An accidental Magritte painting in Bundoora
German reconnaissance platoon sniper pictured during urban mobility training earlier this year
5001 being divisible by 3 doesnt feel right
Shortcuts to determine if an integer is divisible by:
This is a given.
If the last digit is divisible by 2 (a.k.a. even), then so is the whole number.
If the sum of the digits is divisible by 3, then so is the whole number. The recursivity of this means that if the sum has multiple digits, you can add them up again until you get a single digit and see if it's 3, 6, or 9.
Like the rule for 2, but check if the last two digits are divisible by 4.
If it ends in 5 or 0.
If the rules for both 2 and 3 apply.
No shortcut. Alas.
Like the rules for 2 and 4, but check if the last three digits are divisible by 8. (Yes, this pattern keeps going for 16, 32, etc.)
Like the rule for 3, but the sum of the digits (or the sum of the sum of the digits, etc.) must be 9.
If it ends in 0.
11. Put alternating + and - signs in front of each digit such that the last digit has a + sign (so for 5001 it's - 5 + 0 - 0 + 1). If the answer is divisible by 11, so is the original number. This is recursive like the 3 and 9 rules.
my favourite rule for 7: add five times the last digit to the rest. repeat if necessary. e.g. 4886 → 488+(6*5) = 518 → 51+(8*5) = 91 → 9+5=14. and 14 is divisible by 7 :)
OK, here we go!
Assume our number is a multiple of 7 - i.e. it's congruent to 0 mod 7. I'm using letters to represent the digits here, but there could be an arbitrarily large number of digits, hence the ellipsis.
Each digit is multiplied by a progressively higher power of 10.
Now 10 is congruent to 3 mod 7, so we can replace all the 10's with 3's.
A bit of rearranging gives us this way of expressing the last digit a in terms of the other digits.
When we take all the digits except the last one and move them down one place, we're dividing everything by 3.
Here's where 5 being the multiplicative inverse of 3 mod 7 comes in. Dividing by 3 is the same as multiplying by 5.
Speaking of multiplying by 5, let's do that to our alternative expression for a, and add it on.
Everything cancels out and we get 0.
So if our original number was a multiple of 7, doing this trick will also give us a multiple of 7.
"What about the converse?" you might ask.
If our original number isn't divisible by 7, we get a copy of the remainder in our expression for a. Then instead of cancelling down to 0, we'll be left with 5 times the remainder. This won't be 0 because 7 is prime, and so no non-zero numbers will multiply to make 0 mod 7.
(Also someone else posted an alternative 7 trick which is secretly exactly the same as this. Instead of multiplying the last digit by 5 and adding, they multiplied by 2 and subtracted. But 5 = -2 mod 7, so it's just your trick in disguise!)