Pythagoras' theorem: A PROOF
Remember that theorem about right-angled triangles from school?
The one that you had to do endless examples of for homework to cement it into your brain?
Well, you know what your teachers never showed you? The cool bit. The (or rather a) PROOF. The easy, straight forward proof.
Now those four triangles are exactly the same (or rather congruent) size wise. You may skip to next paragraph if convinced: They have two sides equal length - a and b - and right angle between those two sides (as it’s a square). According the funky side angle side rule (proof you may look up if you wish) and the fact they are equal, they are the same.
This of course means the third side is the same - called c. and of course lastly we know that diamond in the middle is also a square too (hurrah!)
So let’s look at the area of this whole square. We have two expressions for it.
1) using the formula for area of triangle 1/2 x base x height = 1/2 ab, and area of a square = c^2, multiplying your triangle area by four we have and simplifying…
Area of big square = 4(1/2 ab) + c^2 = 2ab + c^2
2) using the fact that one side of our big square is a + b
Area of big square = (a + b)^2 = a^2 + 2ab + b^2
Now for the triumphant part – equate and cancel!
2ab + c^2 = a^2 + 2ab + c^2
Now take away 2ab from both sides et voila
Or another even more geometric way is taking a look at this first figure
You can clearly see the formula!
Now you can impress all your friends and inspire the world with the cool side of maths