- taken from “Experiments in Motion Graphics” - 1968 by John H. Whitney
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@effyeahmath
- taken from “Experiments in Motion Graphics” - 1968 by John H. Whitney
(my audio)
184 birds, 140 house guests and 40 cows are not gifts you give to someone you like, much less your “true love.”
Math tip: if there's a number in geometry, it's in Q[√2, π].
So the exponential function is given by
which evaluated at a real number x gives you the value eˣ, hence the name. There are various ways of extending the above definition, such as to complex numbers, or matrices, or really any structure in which you have multiplication, summation, and division by the values of the factorial function at whatever your standin for the natural numbers is.
For a set A we can do some of these quite naturally. The product of two sets is their Cartesian product, the sum of two sets is their disjoint union. Division and factorial get a little tricky, but in this case they happen to coexist naturally. Given a natural number n, a set that has n! elements may be given by Sym(n), the symmetric group on n points. This is the set of all permutations of {1,...,n}, i.e. invertible functions from {1,...,n} to itself. How do we divide Aⁿ, the set of all n-tuples of elements of A, by Sym(n) in a natural way?
Often when a division-like thing with sets is written like A/E, it is the case that E is an equivalence relation on A. The set of equivalence classes of A under E is then denoted A/E, and called the quotient set of A by E. Another common occurence is when G is a group that acts on A. In this case A/G denotes the set of orbits of elements of A under G. This is a special case of the earlier one, where the equivalence relation is given by 'having the same orbit'. It just so happens that the group Sym(n) acts on naturally on any Aⁿ.
An element of Aⁿ looks like (a[1],a[2],...,a[n]), and a permutation σ: {1,...,n} -> {1,...,n} acts on this tuple by mapping it onto (a[σ(1)],a[σ(2)],...,a[σ(n)]). That is, it changes the order of the entries according to σ. An orbit of such a tuple under the action of Sym(n) is therefore the set of all tuples that have the same elements with multiplicity. We can identify this with the multiset of those elements.
We find that Aⁿ/Sym(n) is the set of all multisubsets of A with exactly n elements with multiplicity. So,
is the set of all finite multisubsets of A. Interestingly, some of the identities that the exponential function satisfies in other contexts still hold. For example, exp ∅ is the set of all finite multisubsets of ∅, so it's {∅}. This is because ∅⁰ has an element, but ∅ⁿ does not for any n > 0. In other words, exp 0 = 1 for sets. Additionally, consider exp(A ⊕ B). Any finite multisubset of A ⊕ B can be uniquely identified with an ordered pair consisting of a multisubset of A and a multisubset of B. So, exp(A + B) = exp(A) ⨯ exp(B) holds as well.
For A = {∗} being any one point set, the set Aⁿ will always have one element: the n-tuple (∗,...,∗). Sym(n) acts trivially on this, so exp({∗}) = {∅} ⊕ {{∗}} ⊕ {{∗∗}} ⊕ {{∗∗∗}} ⊕ ... may be naturally identified with the set of natural numbers. This is the set equivalent of the real number e.
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Tres en raya a otro nivel
I would call this n-dimensional non-consecutive tic-tac-toe. Where n is the number of matryoshka dolls where one matryoshka covers another. Or nesting count.
Usually there is a finite number of combinations in tic-tac-toe, with a minimum of 3 moves to win, but the number of combinations would increase for every overlap/nesting a doll makes. And the minimun number of moves would depend on number of matryoshka dolls.
Also lets not forget the combinations in which the dolls can nest, if you remember fron middle school (highschool for you westeners) it a factorial math problem. Which is always fun to do!
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Millie’s Math House, 1990′s
Studying biology: :)
Having to study maths and chemistry in order to fully understand biology: :(
Won’t that only solve 75% of your problems?
The book solves half of your problems, not all of them
Say you have 8 problems. You read the book, and you have 4 problems. You read the book again gets rid of HALF, of those 4 problems. So you’re left with two. Out of the 8 problems, 6 were resolved and 6/8 is 75%.
Finally Tumblr can do math
So, what you’re saying, is that if I buy infinite books, I will solve all of my problems, because the sum as n approaches infinity starting at 1 of (½)^n equals 1, which would be 100% of my problems.
No, you will only ever be able to become infinitely close to solving all of your problems, like this:
Please stop explaining math to me im gay
that’s why radioactive material is such a bitch! it only ever deteriorates relative to its mass so it will never completely vanish
This post is pushing me to the limit
math tip: Sometimes commutative diagrams are not in fact the clearest most elegant way to present a proof.
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Reblog this for luck in love, for Venus to watch over you & to be able to find yourself & others who are good for you.
Reblog to imbue love in your current relationships, to assist in finding a new one, to help heal from past ones & in order to obtain a loving and committed relationship.
Reblog in order to maintain, reblog to persevere, reblog to commit, seek loyalty, and to love wholeheartedly.
Reblog for love for the years to come. Reblog for the love you want. Reblog in hopes of a fairytale, reblog to make that dream come true.
Reblog for love, for me, & for you.