#aptitude-test

[bearingacademyedu]

How the Strong Interest Inventory® Assessment (SII) Can Help You Find the Right Career

The Strong Interest Inventory assessment, also known as SII is a career assessment tool that helps individuals identify their interests as one of the most widely used career assessment tools globally to make informed decisions about their education and careers. 

Invented by Briggs-Meyers Company, the SII is based on the work of psychologist Edward K. Strong Jr., who believed that individuals are most likely to be successful in careers that match their interests.  The SII measures a person’s interests in six broad areas: 

Keep reading: https://www.bearing-academy.com/how-the-strong-interest-inventory-assessment-SII-can-help-you-find-the-right-career

[passpsychometric-blog]

Verbal Reasoning Test

Enjoy our online verbal reasoning test practice and personality test strategies/aptitude test tips. Here we offer the many packages for the candidates which they can choose as per their requirement.

[learningpundits]

Tips on Answering Aptitude Questions on Ages

4 TIPS on cracking Aptitude Questions related to Age

Tip #1: Choose only one variable to solve the problem

Question: Mindy’s current age is 3 times that of her daughter, Cindy. 4 years ago, Mindy’s age was 4 times that of her daughter, what will be Cindy’s age 5 years from now?  

Solution:

Let Cindy’s current age be x. Then Mindy’s age is 3x.

According to the question,

3x-4=4(x-4)

Or, 3x-4=4x-16

Or, x=12.

Thus, 5 years from now, Cindy’s age will be 12+5=17years.

Note: More often than not, this type of questions usually contain ages of different people and at different points in time. While you could choose more than one variable to solve the problem at hand, it is always faster and easier to choose one age as x and then relate all the other ones to it according as stated in the question.

Tip #2: If the question contains ages at different points of time, choose the present age as ‘x’

Question: Ten years from now, Rachel will be three times older than she is today. What is her current age?

Solution:

Let current age be x.

Then, according to the question,

x+10= 3x

=>   2x=10

=>   x=5

Note: Age related problems usually contain references to present, past, and future. It is important to choose correctly which one to consider as our variable so as to reach the solution at the quickest. In order to do so, it is best to choose the present age as ‘x’.

Tip #3: In questions containing the ages of different people, consider the age of the youngest person to be ‘x’

Question: John’s father is 5 times older than John and John is twice as old as his sister Alice. In two years’ time, the sum of their ages will be 58. How old is John now?

Solution:

Let Alice’s current age be x. Then John’s age=2x and their father’s age is 10x.

According to the question,

(x+2)+ (2x+2) + (10x+2) =58

=>   13x=58-6

=>    x=4

=>    John’s present age=10x4=40 years.

Note: Most of the times, these problems mention more than one person’s age that are correlated. It is best to choose the age of the youngest person as x and then relate everyone else’s age to x.

Tip #4: Read the question very carefully. The phrase ‘n time more than’ needs to be understood correctly:

Question: A’s age is twice greater than B’s. If the sum of their ages is 24, what is A’s age?

Solution:

Let B’s age be x.

Then A’s age= x + 2x= 3x (and not 2x)

Now, x+3x= 24

Or, x= 6.

A’s age is 3x= 18 years

Question: Mary is three times as old as her son. In 12 years, Mary's age will be one year less than twice her son's age. How old is each now?

Solution:

Let the son’s age be x. Then Mary’s age= 3x.

Given,

3x+12= 2(x+12) – 1

=>    3x+12= 2x+ 23

=>    x=11

=>    Mary’s age= 33 years, Son’s age= 11 years.

That wraps up our tips for solving Age-type Questions. All the best.

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