Find the remainder in seconds
Divisibility Rule of 7,11 & 13: The method to find whether a given number is divisible by 7, 11, and 13 is the same.
Concept: 1001=7×11×13
⇒ 1001 mod 7
⇒ (1000+1) mod 7
⇒ (-1+1) mod 7
The sequence from the right-hand side is + ve and then — ve
Que: Find the sum of the remainders obtained when 23457621835927189342 is divided by 7,11 and 13 separately.
Solution: Divide the given number into pairs of 3 from the right and keep the arithmetic operators + and — in order from the right.
⇒ 23–457+621–835+927–189+342
⇒ (23+621+927+342)-(457+835+189)
⇒ 1913- 1481
⇒ 432
432 mod 7= 5
432 mod 11= 3
432 mod 13= 3
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SI.No. Advance Maths Links 1. Routh's Theorem Click Here 2. Menelaus Theorem Click Here 3. The Pedal and the Orthic Triangle Click Here 4. T
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