learning C++ and electronics: simple program to calculate Charge (I avg) and number of electrons per given unit of time through copper
/*Date: Feb 28, 2016 **Author: A L **Purpose: This programs takes in Amps and time and returns the ** number of electrons passing through a specific time ** and the current (C) or 1A = 1C\s ** based on information from: **Scherz, P., & Monk, S. (2013). Practical electronics for inventors (3rd ed.). McGraw-Hill. ** */ #include <iostream> #include <math.h>
using namespace std;
int main() { //init variables float copper = 0.0; float timeInSec = 0.0; float amps = 0.0; float charge = 0.0; float numOfElectrons = 0.0;
//assignments copper = 1.602 * powf(10.0, -19.0);
//get user input cout << "This programs takes in Amps and time and returns the"; cout << "\nnumber of electrons passing through a specific time"; cout << "\nand the current (C) or 1A = 1C\\s." << endl;
cout << "\nPlease enter the amount of current in amps(A)(eg. 2):"; cin >> amps; cout << "\nPlease enter the time in seconds (eg. 2):"; cin >> timeInSec;
//calculations charge = amps * timeInSec; numOfElectrons = charge / copper;
//output
cout << endl << "\nThe charge that passes a given point in " << timeInSec << " seconds is: " << charge << "C"; cout << "\n The number of electrons passing through with a charge of " << charge << "C" << " is " << numOfElectrons;
return 0; }