Blerg

I'm a human that exists I guess?

[armadillorollup]

know the difference!

[doomtemparts]

one of my friends in a discord server was talking about how they were nervous about their first scheduled acupuncture appointment. another friend offered to do a tarot reading for them. sent this picture.

[frickomode]

they sell items at tjmaxx that even God is not aware of

[duckbunny]

"historically people had servants" incorrect. historically people WERE servants, and many of us still are.

[apolladay]

are you currently in any pain

yes

no

can't tell

Remaining time: 1 day 14 hours

chronic, injury, stomach ache, slept funny or anything counts

[tiktoks-for-dead-pope]

[retrogamingblog2]

[viejospellejos]

[kyleblackpaw]

[somethingusefulfromflorida]

[demolitionbunnies]

i may be having a horrible day but i can always count on bonnie NOT having a horrible day. because there's never a bad day when you're a bunny. you just sleep and eat and shit. it's a great life.

[oneheadtoanother]

[tiktoks-for-dead-pope]

[dduane]

Meanwhile, via Bluesky...

[rogue-ai-cat]

And here is the resulting image. There is at least Someone in the U.K. government who is actually doing their job, and it is Chief Mouser to the Cabinet, Larry the Cat.

Source

[effervescent-fool]

ive never been able to take "climb him like a tree" as a sexual innuendo seriously because i picture climbing a tree in my mind and then i picture a tall man in my mind and when i put those two things together im not seeing anything sexual. im seeing like. circus tricks.

[foxglovedforest]

The kids are aight

[animentality]

[achievement-hunter]

[textandimageenjoyer]

[dajo42]

5001 being divisible by 3 doesnt feel right

[dajo42]

[shinyhappygoth]

Shortcuts to determine if an integer is divisible by:

This is a given.

If the last digit is divisible by 2 (a.k.a. even), then so is the whole number.

If the sum of the digits is divisible by 3, then so is the whole number. The recursivity of this means that if the sum has multiple digits, you can add them up again until you get a single digit and see if it's 3, 6, or 9.

Like the rule for 2, but check if the last two digits are divisible by 4.

If it ends in 5 or 0.

If the rules for both 2 and 3 apply.

No shortcut. Alas.

Like the rules for 2 and 4, but check if the last three digits are divisible by 8. (Yes, this pattern keeps going for 16, 32, etc.)

Like the rule for 3, but the sum of the digits (or the sum of the sum of the digits, etc.) must be 9.

If it ends in 0.

[zykamiliah]

#THIS POST IS WRONG 7 DOES HAVE A RULE FOR HOW TO TELL IF THE NUMBER IS DIVISIBLE#it's just. not a short cut#you're better off dividing it and seeing if you get a whole number than doing the method

but what IS the rule @anqelbean ???

[anqelbean]

Okay, so, basically, you remove the least important digit of the number (which is the first digit from the right), you double it, and then subtract it from the remaining number. If the number you get is still large, you do it again.

For example, 294

29 4

4×2=8

29-8=21

21 is divisible by 7

Second example, 1946

194 6

6×2=12

194-12=182

182 is still large, so let do it again

18 2

2×2=4

18-4=14

14 is divisible by 7

[blackjame]