There came another question but this time it is related to thermodynamics. Read it and make yourself clear.
If P = A/B, P and B should be inversely proportional to get A. But why in the physics formula S = Q/T + friction, as temperature (T) increases, entropy (S) increases? They should be inversely proportional, isn't they?
ANSWER:
As you suggested, P=A/B i.e PB=A
Then, P is inversely proportional to B, but it's only when A remains constant. Mind it!
This emplies that lower the value of B, the higher must be P as their product is always constant (A)
Now coming to your expression for calculation of entropy, S=Q/T is absolutely wrong as we cannot calculate the absolute value of entropy using this formula.
Rather we can calculate, the change in entropy i.e. ∆S=Q/T
This expression with similar arguments, conveys that if Q remains constant. ∆S is inversely proportional to T.
This formula doesn't at all says that as temperature increases, entropy decreases. Rather, it says that when temperature increases the change in entropy decreases i.e. same amount of heat added to lower temperature causes greater randomnesses and hence entropy change is inversely proportional to temperature.
Absolute value Entropy always increases with temperature. But at lower temperature it increases drastically. Then, at comparitively higher temperature when same amount of heat is added.
This is in accordance with the fact, that temperature it self is the measurement of chaotic movement (kinetic theory of gases). At lower temperature, there is less chaotic movement and slight heat added to system at that temperature would increase the randomnesses (entropy) drastically.
But, at higher temperature there is already much chaos between molecules and slight amount if heat added will not show any considerable changes in the chaos (entropy) caused by molecules.
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