Happiness Will Come To You.
when tho
When You Least Expect It. Probably Late March
reblog for happiness to come for you in late march!
Three Goblin Art
No title available
Not today Justin
Game of Thrones Daily
trying on a metaphor

⁂

No title available
AnasAbdin

izzy's playlists!
No title available

pixel skylines
I'd rather be in outer space 🛸
i don't do bad sauce passes

★

祝日 / Permanent Vacation

Kaledo Art
DEAR READER
Cosimo Galluzzi

roma★
let's talk about Bridgerton tea, my ask is open

seen from Japan

seen from United Kingdom
seen from United States
seen from Brazil

seen from Canada
seen from United Kingdom

seen from United States

seen from Singapore
seen from United States
seen from China

seen from United States
seen from Switzerland

seen from United Kingdom

seen from United Kingdom

seen from South Africa

seen from United States
seen from Germany

seen from Argentina
seen from Canada
seen from United States
@mathsmathsmaths
Happiness Will Come To You.
when tho
When You Least Expect It. Probably Late March
reblog for happiness to come for you in late march!
Sorry it’s so scribbly if it really is too hard to understand I can type it up just let me know 😊
Hello again!
Long time no post! I’m going to be posting again over the next few months as I’m helping my sister get her gcse in maths! So look out for some gcse related maths, hope it can help some of you 😊
Okay I'm back with the mark sceme now!
b)i) I was right, it is 0 for the answer. This is because when you are calculating probabilities with a normal distribution (or any continuous one) you have to work out an area under the graph, so it has to be less than, more than, or between two values, since jst a line on a graph doesnt have an area.
ii) I was right with what I first started saying. Do 1-probability from former question, then do it to the power 6.
iii)Now the seccond way i was trying to do the other one is what you do for this one. You want to work out the distribution for Xbar, which is (using central limit theorum and because it was a normal distribution anyways) a normal distribution. So Xbar~N(original mean,varience divided by 6) since n=6 days. Now do the same as in the first question, using them new values to get a Z value, so then you are working out P(Xbar < 60).
(If it helps the mark sceme says to watch for the two answers being switched round for ii) and iii) so I was obviously not the only one that switched/nearly switched the two methods round! )
Okay the first bit is just a normal distribution. you have X~N(65,202). Draw a picture!
You then need to translate that into Z instead of X, using the equation: Z=(X - mean) divided by (standard deviation).
Once you have the Z value you can use the tables in the back of the book to find the first probability.
The second one, you need to think about more since the book only has less than probabilities while that is a more than one. Use the fact that hte total area inder the graph is equil to 1 to help.
Now onto b.
I am a bit confised by all this. I'm warnign you that i am just taking some random guesses right now, since I wanna go watch this mermaid programme :/ Ill look into it better when i come back and look at the mark scheeme and all that...
i) since there is only one mark I am tempted to say the answer is 0. but im not atually sure :/ (I fail right now)
ii) Now this probably something to do with question a) ii) since they both involve 60. I would say that you need to work out the probability she compleates it in less than 60 mins on one day. (1-probability worked out in other question) then times that by itself 6 times.
I have just had another thought that maybe it actually wants us to write it as a distribution of a sample. say Y maybe. So Y~N(same mean, varience devided by 6). okay I really have no idea D: I would say go cheak the mark sceme or leave it till later when I am back! (ohh i really am failing at thisssss :( )