Hey! I'm really struggling with physics. Here's one of the many problems: The moon has a mass of 7.36x10^22 kg and moves about the earth in a circular orbit of radius 3.8x10^8 m with a period of 27.3 days. Find the moon's kinetic energy as observed on earth. THANK YOU! I'd like whoever's best at physics! Either Jae or Dr. Math!
We know from circular motion that v=2ㅠr/T, as the speed would be the distance travelled divided by the take taken. Use this equation to find V:V = 2 x ㅠ x (3.8x10^8)/(27.3 daysx24x60x60) Remember that the SI units for time is seconds. This gives us V=1012.25 m/s, or 1.01x10^3 m/s.As we are asking to find the kinetic energy of the moon, substitute the V value into the equation: E(kintetic) = 1/2 x m x v^2E= 1/2 x (7.36x10^22) x (1012.25^2)This gives us E=3.77x10^28 J.
Please feel free to ask us any more questions you may have :D-Jae.







