MATHS HELP

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[wrenchwenches]

[weiwei-uplink]

[hanavesinauttija]

[threebigolsausages-deactivated2]

working on something

[chongoblog]

Oh yeah? If you know numbers so good, solve 3x+1 then

I tried 8 and it immediately went back down to 1 so I’m pretty sure it’s solved. You’re welcome, Pythagoras

[chongoblog]

OH BOY OH BOY I GET TO EXPLAIN 3X + 1

So just “3x +1″ is an expression, not an equation, however it’s also shorthand for an infamous mathematical problem known as the “Collatz Conjecture”. It’s a very, very, VERY simple question that still has mathematicians scratching their heads.

The premise goes like this:

Take a number (a positive integer) and call it “x”.

If that number is even, divide it by 2. If the number is odd, then multiply it by 3 and then add 1 (3x + 1). Repeat over and over again. (so you could go 3, 3(3) + 1 = 10, 10/2 = 5, 3(5) + 1 = 16, etc.)

The Collatz Conjecture (aka the 3x + 1 problem) states that eventually, this sequence will always lead you to the number 1 where it loops 1=>4=>2=>1=>4=>2=>1=>4=>2=>1 forever, regardless of which number you start this sequence with.

Now, there is no proof that this is true or false yet (hence the “conjecture” part).

If you want to disprove the 3x + 1 problem, all that you have to do is find a positive integer that does not ever make it to 1, either by finding a closed loop of numbers that ISNT 1=>4=>2=>1 or by finding a value that just has it keep increasing to infinity (7=>22=>11=>34=>17=>52=>27=>82=>41=>122…..while this sequence does end up coming back down to 1, people theorize there could be a starting point where it just keeps going up and up and up forever). If you can just find ONE, then you will have successfully solved 3x + 1.

But to this day, every single positive integer has been tested from 1 to 2^68 (or approx. 1-300,000,000,000,000,000,000 (300 quintillion). None of them have proven to be an exception.

But any Cookie Clicker veteran knows that 300 quintillion is child’s play. A number that makes an infinitesimal speck of dust look like a god damn multiverse in relation to infinity. And we don’t exist outside of time (yet) so we probably aren’t going to be able to test an infinite number of positive integers.

So if you want to prove the 3x + 1 problem, you gotta make a proof. If you’ve never done mathematical proofs before or don’t know what they are, remember back in school when your teacher gave you those “Solve for x:” questions and you had to move numbers and variables around until you got the right answer? Yeah, you gotta do that. A lot. And you MIIIIIGHT be able to get to the right answer. That triple dot thing from Beginner’s Guide shows up there although it’s upside down apologies I am very tired, and like the Beginner’s Guide, crying once or twice is completely normal and even expected.

But no one has been able to make a proof yet. So there 3x + 1 stands to this day. The most deceptively simple math question that has stumped mathematicians for decades. If you want a more in-depth talk about this problem, this video does a fantastic job going into the details.

Thanks for giving me the chance to talk about math!!!!!

[psychotic-gerard]

important quæstion. wats your favourite maths.

arithmetics

algebra

geometry

calculus

statistics

mechanics

probability

trigonometry

other [put in tags]

i don’t like any maths

Voting ended onJun 22, 2023

[gardavwar]

Big Brain Time

[only-tiktoks]

are you...

pro cleo

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Voting ended onMay 2, 2023

[maths-help]

help! i feel like im going crazy!

my brother and i were watching an anime when a temperature of 39.2°C came up. being american, we only understand Fahrenheit. so, for fun, we decided to see if we could convert it in our heads...

needless to say, we couldnt and ended up looking it up. regardless, later i kept trying to work it out on paper. i finally remembered how, but..... it keeps coming out 1 off??? where am i going wrong! help!!

Hi :D ngl i'm kind of obsessed with your notes, bc you wrote the whole multiplication process down and then checked your answer. anyway let's get right to it:

in your multiplication table for 39.2 * 1.8, the first row is 39.2*0.8=31.36 (correct), and then you did 39.2*1.0=40.20. somewhere you added an additional 1 even though when you write it down like 39.2*1.0 you can see that the 40.20 can't be right.

i hope that helped!

also if you wanna know a temperature in °F but you can deal with a rough estimate, here's what i usually do:

1.8 is almost 2, or, in other words, it is 2-0.2. it's way easier to double a number in your head than do the whole "multiply by 1.8 ... argh how did that work again, i need a pencil" shtick. for the sake of simplicity, let's say you want to know what 39°C are in °F, so you could

multiply by 2: that's 78. an easy way to do this in your head is by calculating 40*2 and then subtracting 2, because 39=40-1, so 39*2 = (40-1)*2=40*2-2

keep the 78 as a preliminary result in your mind. now, shift the decimal one place to the left: 78.0 -> 7.8

subtract these: 78-7.8 = 70.2

now add the 32 and there you got your rough estimate of 39.2°C -> 102.2°F

when you shift the decimal place one to the left (or, divide by 10), you essentially calculate the result of 39*0.2. you could sum up this whole calculation as

39*1.8+32 = (40-1)*(2-0.2)+32 = 40*2-2-(40*2-2)/10 = 78-7.8 = 70.2+32=102.2

-sorrel

[maths-help]

A film starts at 6.40 it lasts 95 minutes what time does the film end

95 minutes = 60 minutes (1 hour) + 30 minutes (half an hour) + 5 minutes

6:40 + 1 hour = 7:40

7:40 + half an hour = 8:10

8:10 + 5 minutes = 8:15

[hilarioushumorfromouterspace]

[maths-help]

Jolene invests her savings in two bank accounts, one paying 4 percent and the other paying 9 percent simple interest per year. She puts twice as much in the lower-yielding account because it is less risky. Her annual interest is 2941 dollars. How much did she invest at each rate?

We will need to use the formula for simple interest which is A = P(1 + rt), where P : Principal (initial investment) r : interest rate (as a decimal) t : time in years We will set up two equations and combine them to solve for P in both.  For the low-yielding (which I will denote with “_low”), we have A_low =  P_low * (1 + r_low * t_low) Similarly, for the high-yielding (which I will denote with “_high”), we have A_high = P_high * (1 + r_high * t_high) Now - what numbers do we get from the question?

We know: r_low = 4 % == 0.04 r_high = 9% == 0.09 t_low = t_high = 1 [year]

We also know that in the end, A_low + A_high = 2941. We also know that P_low = 2 * P_high (as Jolene invests twice as much into P_low as into P_high).

Can you set up the equations and solve it from here?

Here’s my solution:

A_low = P_low * 1.04 A_high = P_high * 1.09

A_low + A_high = 2941 = [P_low * 1.04] + [P_high * 1.09]

using that P_low = 2 * P_high 

<=>  2941 = [(2 * P_high) * 1.04] + [P_high * 1.09]

<=> 2941 = 3.17 * P_high

=> P_high = 927.76 (rounded to the second decimal place, as we’re dealing with money)

=> P_low = 2 * P_high = 1855.52

- K

[maths-help]

The Lines y = X² + 3x - 1 and Y = 2x + 5 intersect at two points. The lines joining the two points has length k√5. Find the value of K. (Hint; Use Pythagoras theorem to find the distance between the two points). I'm soooo confused, please help!! 😭💕💕💕

You can solve this in many ways but the easiest would be simple substitution with putting in y = (2x + 5) in for the left side of the first statement in the place of y.

This will remove y as being a variable and you can figure out x alone.

Which becomes

(2x+5) = x^2 +3x-1

5 + 1 = x^2 +3x -2x

6 = x^2 + x

0 = x^2 +x -6

And now we factor

(X+3)(x-2) =0

So our x intercepts are x= -3 and x = +2

Using either equation above given we sub in the X values to get our y coordinates

Ex.

Y = 2x + 5

[For x = 2]

Y = 2(2) + 5

Y = 9

So (2,9) is one intersection point.

[For x = -3]

Y = 2(-3) + 5

Y = -1

So (-3,-1) is the other point of intersection.

Set up the Distance Formula. The formula states that {\displaystyle d={\sqrt {(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}}},

Now to find the k value you understand that you a^2 + b^2 = c^2 for pythagorean triangle so where your points intercept are the and b values.

So (2,9) is x1,y1

And (-3,-1) is our x2,y2

Use the distance formula and you will solve your problem.

I will let you finish this problem to help you practice. But leave the k solution at the bottom for you.

It seems long but its mostly practice. The more familiar you are with solving two equations the faster you'll handle all future problems :)

Good luck!

D = sqrt(125)

D = sqrt(25 *5)

D = 5* sqrt(5)

K = 5

[maths-help]

3/5 + 7/8

Hi Anon! To add fractions, we need to get them to the same denominator (i.e. the number on the bottom of the fractions needs to be the same).

The lowest common denominator of 5 and 8 is 40.

So 3/5 = (3*8) / (5*8) = 24/40 and 7/8 = (7*5) / (8*5) = 35/40

Add these fractions: 24/40 + 35/40 = 59/40

- Kendra

[maths-help]

The area is 3.0 meters with the radius being 17 meters inside and the outside radius is 20 meters. How many meters is required to form the area

Hi Anon, 

if I interpret your question correctly, the problem is the following:

where r = 17 and R = 20, and we’re trying to figure out the area of the donut between those two radii.

We can do this by calculating the area of the big circle - area of small circle! 

Area of the big circle: A = πR^2 =  π * 20^2 =  π * 400 = 1256.64

Area of the small circle: A = πr^2 =  π * 17^2 =  π * 289 = 907.92

Difference of the two areas: 1256.64 - 907.92 = 348.72

I hope this helps! If your question is different, feel free to send us another message to clarify :)

- Kendra

[maths-help]

What percentage is 5 of 30?

5 goes into 30 exactly 6 times, i.e. 5/30 = 1/6. Thus, we have (5/30) × 100%= 16.666666667%

(if you mean 5% of 30, that would be 

(5/100) * 30 = (5*30)/100 = 150/100 = 1.5

)

Hope this helps!

- Kendra

[klashta-neali]