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Evaluate the improper integral: ∫₀^∞ 1/(1 + x²) dx --------------------------------------------- Solution: Step 1: Recognize the standard integral form. We know that: ∫ 1/(1 + x²) dx = arctan(x) + C Step 2: Apply limits for the improper integral. ∫₀^∞ 1/(1 + x²) dx = lim (b → ∞) ∫₀^b 1/(1 + x²) dx = lim (b → ∞) [arctan(x)]₀^b Step 3: Evaluate the limits. arctan(0) = 0 lim (b → ∞) arctan(b) = π/2 Step 4: Final Answer ∫₀^∞ 1/(1 + x²) dx = π/2
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