#balancing equations

[polarmolecule]

in evil chemistry, the equation balances you

[er-cryptid]

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[ggsstudies]

1/21/19

balancing chem equations :)

xo- gg

[sciencesideanswers]

I need help balancing equations for chemistry I have only a few left; Sodium Hydroxide + sulfuric acid = sodium sulfate + water Fluorine gas + Calcium metal = Calcium Fluoride powder Sodium metal + Iron (II) Chloride = Iron metal + Sodium Chloride I need the balanced equations, thanks for your time

It's al about making the total numbers of each substance match on each side.

So, if you see a value, just multiply it by a number on both sides.

Sodium Hydroxide + Sulfuric acid = Sodium Sulfate + waterNaOH + H2SO4 = Na2SO4 + H20 (unbalanced)

Let's count the atoms on each side. Left side vs right side:

1 Na -- 2 Na5 O -- 5 O3 H -- 2 H1 S -- 1 S

Since this is all about proportions and we cannot change the composition of the formulas, we can only multiply the values that we have, never divide.

It's always easier to pick an unbalanced atom that is only on one component in one side. In this case, Na. Let's multiply the left side by 2 and recount:

2 NaOH + H2SO4 = Na2SO4 + H20 (unbalanced)

Atom count check:

2 Na -- 2 NA6 O -- 5 O4 H -- 2 H1 S -- 1 S

Ok, let's now balance the H, because one of them is just a multiple of the other, and on the right side appears in a single place, so we can just multiply that one by 2.

2 NaOH + H2SO4 = Na2SO4 + 2 H20 (unbalanced)

Atom count check:

2 Na -- 2 Na6 O -- 6 O4 H -- 4 H1 S -- 1 S

Check that out! It is all balanced!

****

Fluorine Gas + Calcium metal = Calcium Fluoride powderF2 + Ca = CaF2

Atom check:

2 F -- 2 F1 Ca -- 1 Ca

Ah, this one was already balanced.

****

Sodium metal + Iron (II) Chloride = Iron metal + Sodium ChlorideNa + FeCl2 = Fe + NaCl

Atom check:

1 Na -- 1 Na1 Fe -- 1 Fe2 Cl -- 1 Cl

Let's balance Cl:

Na + FeCl2 = Fe + 2 NaCl

1 Na -- 2 Na1 Fe -- 1 Fe2 Cl -- 2 Cl

Huh, we unbalanced Na. Let's balance that one now:

2 Na + FeCl2 = Fe + 2 NaCl

2 Na -- 2 Na1 Fe -- 1 Fe2 Cl -- 2 Cl

Balanced!

****

I had completely forgotten how to do these but this very nice video helped me out remember and go through the process:

[senku-ishigami-official]

hey twunc my regionlas is in 3 weeks u better wish upon a fucking star that I win

also how the FUCK do u balance equations

Yeah, yeah, I got your message. Starting to wonder if you spelled "regionals" wrong twice on purpose.

The best way to figure out how to balance chemical equations is to do it in practice. Let's start with something simple.

Fe + Cl2 -> FeCl3

This is clearly unbalanced since there's two chlorine atoms on one side and three on the other. We can fix this by first multiplying the chlorine atoms together to figure out how many we need on each side to keep it balanced. It's basically like adding fractions -- we're finding the common denominator. In this case, it's 6. Two times three.

So now we give each molecule a new coefficient so there are six chlorine atoms on each side.

Fe + 3Cl2 -> 2FeCl3

But now the iron is unbalanced. Not to worry. You can just add another to the reactants since the iron is on its own.

2Fe + 3Cl2 -> 2FeCl3

Now it's balanced.

Let's try a harder one. We're not going to solve this immediately -- it's like a puzzle, you have to keep changing your answer until it fits. So I'll walk you through my thought process.

C6H5COOH + O2 -> CO2 + H2O

Start by counting how many of each atom is on each side. We have 7 carbon, 6 hydrogen, and 4 oxygen in the reactants. In the products, we have 1 carbon, 3 oxygen and 2 hydrogen.

The first thing I notice is the 7 carbons. That's a prime number, so we need our CO2 to be divisible by 7. You can try making the CO2 coefficient 7 but I'm going to make it 14 for the sake of time. Just add a 2 to the front of the benzoic acid.

2C6H5COOH + O2 -> 14CO2 + H2O

Now we need to make our hydrogen fit. Why hydrogen next? In the reactants, oxygen has a whole molecule all to itself, so we can make that whatever it needs to be to fit the other molecules.

Since there are 12 hydrogen in the reactants, make the H2O coefficient a 6. Now you have 12 on both sides.

Yippee!! Carbon and hydrogen are officially balanced, and now all we have left is oxygen, which should be easy since like I said, we can make that O2 coefficient whatever we want.

We have 34 oxygen in the products. There are 4 already accounted for in the benzoic acid, so we have 30 left. So make the O2 coefficient 15 to get 30 oxygen in the reactants.

Your final equation should look like this:

2C6H5COOH + 15O2 -> 14CO2 + 6H2O

And we can't simplify this further. So that's the answer.

If you're doing one with polyatomic ions, just pretend each ion is a single atom. For instance, take this equation.

K(NO3) + Ca(CO3) -> K2(CO3) + Ca(NO3)2

Not balanced. But instead of counting each individual carbon, oxygen, nitrogen etc, you can count each nitrate and carbonate instead. So if you have 2 nitrates and 2 potassium in the products and one of each in the reactants, it would look like this:

2K(NO3) + Ca(CO3) -> K2(CO3) + Ca(NO3)2

Hope this helped. Win.

[bewaretheides]

when your teacher gives you the assignment and it’s something you’re good at and don’t hate, that’s peace

[therealsporcle]

The Unequal Equation Quiz II Quiz

[therealsporcle]

The Unequal Equation Quiz Quiz