artist: felicia chiao
tumblr dot com
i don't do bad sauce passes
Alisa U Zemlji Chuda
dirt enthusiast
cherry valley forever
sheepfilms

Love Begins

★
Claire Keane

roma★
NASA
will byers stan first human second
Mike Driver
DEAR READER
taylor price

Andulka
Not today Justin

Discoholic 🪩

⁂
Three Goblin Art

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@archivistsbelieve
artist: felicia chiao
going over to my minimalist girlfriend’s house and she apologizes profusely for the mess and there’s just a single perfect, fresh pea on the floor of her living room
Blue Lois
can i help you
Red Marge
jesus christ. I Am Under Fucking Attack
World Heritage Post
i deserve a medal for this post. not because i was particularly funny but because i survived an onslaught of nearly one hundred gimmick blogs in the wake of this post popping off, and the fact that i didn’t try to track any of them down and snuff them out with my bare hands is a testament to my immeasurable strength and should be rewarded. at one point i had “the official letter h” add on to this post. you wanna know that blog’s gimmick? the really funny and original and worthwhile gimmick the official letter h blog had? yep you guessed it they just gave me the god damned letter H and then fucked off. only jesus knows the suffering i endured over that harsh winter, and he wept for me
game: has any kind of elemental based fighting system
me: apply pokemon logic
To be fair Pokemon element logic is rooted in normal logic.
yeah, everyone knows a wrestlers biggest weakness is the local pigeons
go outside and try to suplex a bird
tell me how bug resists fighting
go outside and try to suplex a bug
World Heritage Post
Brooch by Marcus & Co., 1900. The Newark Museum of Art.
Knightposting this princessposting that WHO IS TILLING THE FIELDS
You don't hear from the field workers because they aren't "posting"
They're serfing the internet
there are no serfposts because they were almost exclusively illiterate
that doesn’t stop most tumblr users
how dare you say we surf on the poor
The freak is standing on my back, displeased. I have not met his daily cuddles quota
Morning on the Seine at Giverny 02, 1897, Claude Monet
just some of the the changes in design for the Penguin Symbol on old Penguin Paperbacks
mh computer tryin to say chimichangas I give uP
sometimes artists worry if their art is actually capable of making the world a better place, or if its all just wasted effort. what you need to remember is: all art is evil, and the sole aspiration of the artist should be to maim as many onlookers as possible.
why did you people come up with russian names for what is supposed to be a movie set in italy. what was the thought process here. why does she sound like she walked out of a tolstoy novel
an insane response, but i can't fight this. carry on
im being hunted for sport in the notes
silly salt cellar
the older i get the more unnecessary it seems to tell people my business
I don't think this is possible????
Hello Ryan I am here to help. So the first step is pretty easy: Three cheeseburgers are worth 18, so each one is worth 6. If these are dollars, that's a steal!
From the second equation we get that cheeseburger plus fries-squared is five. Subtracting cheeseburger, which is six, from both sides, we get that fries-squared is negative-one. Math fans will know that there are two solutions to this; either fries are the "imaginary unit" 𝒾 or they are its negative, -𝒾. We'll do the rest of the problem with 𝒾, keeping in mind that at the end we should also take the complex conjugates as solutions.
Finally, we have that cup to the power of fries, minus cup, equals three. Replacing fries with 𝒾, and moving a cup to the other side, we get that cup-to-the-𝒾 is equal to cup-plus-three.
Now, the weird part about this is the cup-to-the-i. The problem with this is that complex exponentiation is technically not a thing. That is to say, there is no one function which is mathematically equal to "input-to-the-power-of-𝒾". In fact, there are infinitely many such functions.
Fortunately, due to reasons that take about six pages to explain (trust me I've done it), there is one particular function that many people have agreed is "the most reasonable one". This is not a mathematical notion, but a human preference. Seeing as this question was presumably written by a human, I am comfortable with using this function.
So, what function is this? Well, given a complex number r∠θ written in polar form (if you don't know what that means don't worry), where -π < θ ≤ π, then (r∠θ)^𝒾 = e^(-θ)∠ln(r).
Applying this to our problem a value r∠θ will be a possible solution for cup if e^(-θ)∠ln(r) = r∠θ + 3. Splitting this into real and imaginary parts, we get two equations: e^(-θ) cos(ln(r)) = r cos(θ) + 3 and e^(-θ) sin(ln(r)) = r sin(θ). We can graph these equations on Desmos:
The possible values of cup are the intersections between the red, green, and purple. There are infinitely many of these which have an angle of around -π/3, and there are two weirdos: One which is a complex number very close to -2.98, and one which is somewhere around -25. The possible values for cup are all of these infinitely many solutions, and also all of their complex conjugates.
They were right, 99% of people can't solve it.
i've actually been working on some formulae to give all possible solutions to complex exponentiation problems recently, so here's my take on this:
let the value of the glass = z, for z ∈ ℂ:
z^(±i) = 3+z
let z = r·e^(iθ) for r,θ ∈ ℝ, -π < θ ≤ π
∴ z = r·e^i(θ+2πn) for all n ∈ ℤ
∴ (r·e^i(θ+2πn))^(±i) = 3+r·e^i(θ+2πn)
distribute powers (apologies for the use of ∓):
r^(±i)·e^(∓(θ+2πn)) = 3+r·e^i(θ+2πn)
convert to the same base:
e^i(±ln(r))·e^(∓(θ+2πn)) = 3+r·e^i(θ+2πn)
split into real and imaginary components:
re: cos(±ln(r))·e^(∓(θ+2πn)) = 3+r·cos(θ)
im: sin(±ln(r))·e^(∓(θ+2πn)) = r·sin(θ)
in effect, all this changes is the restriction on the domain of theta to be between -pi and pi, so you can just ignore that constraint.